计算和的最大积相关题目描述及相关代码

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2026-01-14 10:34:26 +08:00
parent d3099866fb
commit ff3680c16a
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def integer_break(n):
key_map = {1: 1, 2: 1, 3: 2, 4: 4}
if n in key_map:
return key_map.get(n)
# n>5
tmp = n % 3
r = 0
if tmp == 1:
k = (n - 4) // 3
tmp = 4
elif tmp == 2:
k = (n - 2) // 3
else:
k = n // 3
tmp = 1
return pow(3, k) * tmp
print(integer_break(10))